REVISION SUMMARY: Introduction to Trigonometry (NCERT Class 10)
Definitions (exactly as framed):
- In right △ABC right-angled at B, for acute ∠A:
sin A = BC/AC (opposite/hypotenuse),
cos A = AB/AC (adjacent/hypotenuse),
tan A = BC/AB (opposite/adjacent),
cosec A = AC/BC = 1/sin A,
sec A = AC/AB = 1/cos A,
cot A = AB/BC = 1/tan A.
- sin 0° = 0, cos 0° = 1; tan 0° = 0, cot 0° undefined, sec 0° = 1, cosec 0° undefined.
- sin 90° = 1, cos 90° = 0; tan 90° undefined, cot 90° = 0, sec 90° undefined, cosec 90° = 1.
Standard results (no proof required beyond NCERT derivation): - tan A = sin A / cos A and cot A = cos A / sin A. - Trigonometric ratios of ∠A are identical in any right triangle containing the same acute angle (via AA similarity of △PAM ~ △CAB, etc.). - sin A and cos A are always ≤ 1; sec A and cosec A are always ≥ 1 (hypotenuse is longest side).
Trigonometric identities (proved in text; students must reproduce proofs in exams): - cos²A + sin²A = 1 (0° ≤ A ≤ 90°). - 1 + tan²A = sec²A (0° ≤ A < 90°). - 1 + cot²A = cosec²A (0° < A ≤ 90°).
| Ratio | Definition | Symbol Meaning |
|---|---|---|
| sin A | opposite / hypotenuse | BC/AC |
| cos A | adjacent / hypotenuse | AB/AC |
| tan A | opposite / adjacent | BC/AB |
| cosec A | hypotenuse / opposite | AC/BC = 1/sin A |
| sec A | hypotenuse / adjacent | AC/AB = 1/cos A |
| cot A | adjacent / opposite | AB/BC = 1/tan A |
Standard values table (NCERT Table 8.1)
∠A | 0° | 30° | 45° | 60° | 90°
sin A | 0 | 1/2 | 1/√2 | √3/2 | 1
cos A | 1 | √3/2 | 1/√2 | 1/2 | 0
tan A | 0 | 1/√3 | 1 | √3 | not defined
cosec A | not defined | 2 | √2 | 2/√3 | 1
sec A | 1 | 2/√3 | √2 | 2 | not defined
cot A | not defined | √3 | 1 | 1/√3 | 0
Type 1: Find remaining ratios when one ratio is given
Draw right triangle, assign sides in the given ratio (using k), apply Pythagoras to find third side, then write all six ratios.
Type 2: Prove two acute angles equal if their trigonometric ratios are equal
Assume sin B = sin Q (or cos A = cos B), form two right triangles, show corresponding sides proportional, apply AA similarity (Theorem 6.4) to conclude ∠B = ∠Q.
Type 3: Evaluate expressions using standard values or identities
Substitute exact values from the table or apply sin²A + cos²A = 1, 1 + tan²A = sec²A, etc., and simplify.
Type 4: Verify or prove trigonometric identities
Start from LHS, convert all terms to sin/cos (or tan/sec), apply Pythagoras-derived identities, reduce to RHS. Keep domain restrictions in mind.
Type 5: Find sides/angles in a right triangle using ratios
Select the ratio linking known and unknown quantities (e.g., tan C for adjacent side), solve; use Pythagoras as alternative check.
Type 6: Solve equations involving trigonometric ratios of (A ± B)
Convert to known standard angles (30°, 45°, 60°), solve simultaneous linear equations for A and B.
A study aid reviewed by GFIS faculty — always verify with your textbook and teacher.